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Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.?
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Two identical charged particles each having a mass 10g and charge 2 × ...
Given data:
- Mass of each particle, m = 10g = 0.01kg
- Charge of each particle, q = 2 × 10^-7 C
- Coefficient of friction, μ = 0.25
Equilibrium condition:
When the two particles are separated by a distance L and are in equilibrium, the electrostatic force between them will be balanced by the frictional force.
Electrostatic force:
The electrostatic force between the two particles is given by Coulomb's law:
F = k * (q^2) / L^2
where k is the electrostatic constant (9 × 10^9 Nm^2/C^2).
Frictional force:
The frictional force acting on each particle is given by:
f = μ * m * g
where g is the acceleration due to gravity (9.8 m/s^2).
Equilibrium condition:
For equilibrium, the electrostatic force and the frictional force must balance each other:
k * (q^2) / L^2 = μ * m * g
Solving for L:
L = sqrt(k * (q^2) / (μ * m * g))
Substitute the values:
- k = 9 × 10^9 Nm^2/C^2
- q = 2 × 10^-7 C
- m = 0.01kg
- μ = 0.25
- g = 9.8 m/s^2
Calculate:
L = sqrt((9 × 10^9 * (2 × 10^-7)^2) / (0.25 * 0.01 * 9.8))
L = sqrt(36)
L = 6 meters
Therefore, the separation distance between the two particles for them to stay in equilibrium is 6 meters.
Given data:
- Mass of each particle, m = 10g = 0.01kg
- Charge of each particle, q = 2 × 10^-7 C
- Coefficient of friction, μ = 0.25
Equilibrium condition:
When the two particles are separated by a distance L and are in equilibrium, the electrostatic force between them will be balanced by the frictional force.
Electrostatic force:
The electrostatic force between the two particles is given by Coulomb's law:
F = k * (q^2) / L^2
where k is the electrostatic constant (9 × 10^9 Nm^2/C^2).
Frictional force:
The frictional force acting on each particle is given by:
f = μ * m * g
where g is the acceleration due to gravity (9.8 m/s^2).
Equilibrium condition:
For equilibrium, the electrostatic force and the frictional force must balance each other:
k * (q^2) / L^2 = μ * m * g
Solving for L:
L = sqrt(k * (q^2) / (μ * m * g))
Substitute the values:
- k = 9 × 10^9 Nm^2/C^2
- q = 2 × 10^-7 C
- m = 0.01kg
- μ = 0.25
- g = 9.8 m/s^2
Calculate:
L = sqrt((9 × 10^9 * (2 × 10^-7)^2) / (0.25 * 0.01 * 9.8))
L = sqrt(36)
L = 6 meters
Therefore, the separation distance between the two particles for them to stay in equilibrium is 6 meters.
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Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.?
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Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.?.
Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical charged particles each having a mass 10g and charge 2 × 10^-7 C are placed on a horizontal table with a separated of L between them such that they stay in limited equilibrium. if the coefficient of friction between each particle and the table is 0.25, find the value of L.?.
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