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Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example is

 
  • a)
    H2O
  • b)
    HCl
  • c)
    HNO3
  • d)
    H2SO4
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Elements in which apart from 3s and 3p orbitals, 3d orbitals also avai...
In H2SO4, S has more than 8 electrons in the valence shell.
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Most Upvoted Answer
Elements in which apart from 3s and 3p orbitals, 3d orbitals also avai...
The structure of H2SO4 contains central S atom and is bonded to two oxygen are doubly bonded and two hydroxide groups..
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Elements in which apart from 3s and 3p orbitals, 3d orbitals also avai...
Explanation:
In the given question, we are asked to identify the compound in which apart from 3s and 3p orbitals, 3d orbitals are also available for bonding. Let's analyze each option to find the correct answer.

a) H2O:
Water (H2O) is a compound where oxygen (O) is the central atom. Oxygen has 2s, 2p, and 2d orbitals available for bonding. However, in water, only the 2s and 2p orbitals of oxygen participate in bonding with the hydrogen atoms. Therefore, option 'a' is not the correct answer.

b) HCl:
Hydrogen chloride (HCl) is a compound where chlorine (Cl) is the central atom. Chlorine has 3s, 3p, and 3d orbitals available for bonding. However, in HCl, only the 3s and 3p orbitals of chlorine participate in bonding with the hydrogen atom. Therefore, option 'b' is not the correct answer.

c) HNO3:
Nitric acid (HNO3) is a compound where nitrogen (N) is the central atom. Nitrogen has 2s, 2p, and 2d orbitals available for bonding. However, in HNO3, only the 2s and 2p orbitals of nitrogen participate in bonding with the hydrogen atoms and oxygen atoms. Therefore, option 'c' is not the correct answer.

d) H2SO4:
Sulfuric acid (H2SO4) is a compound where sulfur (S) is the central atom. Sulfur has 3s, 3p, and 3d orbitals available for bonding. In H2SO4, all these orbitals of sulfur can participate in bonding. Sulfur forms four covalent bonds with four oxygen atoms, and the remaining two hydrogen atoms are bonded to oxygen atoms. This results in sulfur having more than eight valence electrons around it, which is possible due to the presence of 3d orbitals. Therefore, option 'd' is the correct answer.

Conclusion:
Among the given options, the compound H2SO4 is the correct answer as it contains a central atom (sulfur) with 3d orbitals available for bonding, resulting in more than eight valence electrons around the central atom.
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Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example isa)H2Ob)HClc)HNO3d)H2SO4Correct answer is option 'D'. Can you explain this answer?
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Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example isa)H2Ob)HClc)HNO3d)H2SO4Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example isa)H2Ob)HClc)HNO3d)H2SO4Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example isa)H2Ob)HClc)HNO3d)H2SO4Correct answer is option 'D'. Can you explain this answer?.
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