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A block is at rest on an inclined plane making an angle α with the horizontal. As the angle α of the incline is increased, the block starts slipping when the angle of inclination becomes θ. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ to horizontal. Then coefficient of friction is equal to
  • a)
    sin θ
  • b)
    cos θ
  • c)
    tan θ
  • d)
    Independent of θ
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A block is at rest on an inclined plane making an angle α with the hor...
Explanation:
- Angle of Inclination:
- When the block is at rest on the inclined plane, the angle of inclination is α.
- The block starts slipping when the angle of inclination becomes θ.
- Coefficient of Static Friction:
- The coefficient of static friction between the block and the surface of the inclined plane is μ.
- Force Components:
- The force of gravity acting on the block can be resolved into two components:
- Normal force (perpendicular to the incline)
- Force parallel to the incline
- Frictional Force:
- The maximum static frictional force that can act on the block is given by:
- μ * N, where N is the normal force
- Equilibrium Condition:
- At the point when the block is about to start sliding, the component of the force of gravity parallel to the incline is equal to the maximum static frictional force:
- mg * sin(θ) = μ * N
- mg * sin(θ) = μ * mg * cos(θ)
- tan(θ) = μ
- Conclusion:
- Therefore, the coefficient of friction μ is equal to tan(θ) when the block starts sliding down at an angle θ to the horizontal.
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A block is at rest on an inclined plane making an angle α with the horizontal. As the angle α of the incline is increased, the block starts slipping when the angle of inclination becomes θ. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ to horizontal. Then coefficient of friction is equal toa)sin θb)cos θc)tan θd)Independent of θCorrect answer is option 'C'. Can you explain this answer?
Question Description
A block is at rest on an inclined plane making an angle α with the horizontal. As the angle α of the incline is increased, the block starts slipping when the angle of inclination becomes θ. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ to horizontal. Then coefficient of friction is equal toa)sin θb)cos θc)tan θd)Independent of θCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block is at rest on an inclined plane making an angle α with the horizontal. As the angle α of the incline is increased, the block starts slipping when the angle of inclination becomes θ. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ to horizontal. Then coefficient of friction is equal toa)sin θb)cos θc)tan θd)Independent of θCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block is at rest on an inclined plane making an angle α with the horizontal. As the angle α of the incline is increased, the block starts slipping when the angle of inclination becomes θ. The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle θ to horizontal. Then coefficient of friction is equal toa)sin θb)cos θc)tan θd)Independent of θCorrect answer is option 'C'. Can you explain this answer?.
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