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Solution to (2x+3)²+ (2x-3)² = (8x+6) (x-1)?
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Solution to (2x+3)²+ (2x-3)² = (8x+6) (x-1)?
Given Equation:
(2x+3)² + (2x-3)² = (8x+6) (x-1)

Solution:

Expand the left side of the equation:
(2x+3)² = (2x+3)(2x+3) = 4x² + 12x + 9
(2x-3)² = (2x-3)(2x-3) = 4x² - 12x + 9

Substitute the expanded forms back into the equation:
4x² + 12x + 9 + 4x² - 12x + 9 = (8x+6)(x-1)

Combine like terms on the left side:
8x² + 18 = (8x+6)(x-1)

Expand the right side of the equation:
(8x+6)(x-1) = 8x² - 8x + 6x - 6 = 8x² - 2x - 6

Set the left side equal to the right side:
8x² + 18 = 8x² - 2x - 6

Subtract 8x² from both sides:
18 = -2x - 6

Add 6 to both sides:
24 = -2x

Divide by -2:
x = -12

Conclusion:
The solution to the equation (2x+3)² + (2x-3)² = (8x+6) (x-1) is x = -12.
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Solution to (2x+3)²+ (2x-3)² = (8x+6) (x-1)?
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