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46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed
(A) 1
(B) * 1 / 2
(C) * 1 / 6
(D) 1/3?
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46. An aqueous solution containing KIO3 was treated with an excess of ...
Calculation of Millimoles of KIO3 Consumed
- **Step 1: Reaction**
- KIO3 + 5KI + 3HCl → 3I2 + 3KCl + 3H2O
- **Step 2: Stoichiometry**
- From the reaction, 1 mol of KIO3 reacts with 5 mol of Kl to produce 3 mol of I2
- Since 1 mol of I2 reacts with 2 mol of Na2S2O3, 1 mol of KIO3 will consume 10/2 = 5 ml of 0.1M Na2S2O3
- **Step 3: Calculation**
- Since 1 mol of KIO3 consumes 5 ml of 0.1M Na2S2O3, the millimoles of KIO3 consumed = 5 x 0.1 = 0.5 mmol
Therefore, the correct answer is (B) 1/2.
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46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed(A) 1(B) * 1 / 2(C) * 1 / 6(D) 1/3?
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46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed(A) 1(B) * 1 / 2(C) * 1 / 6(D) 1/3? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed(A) 1(B) * 1 / 2(C) * 1 / 6(D) 1/3? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed(A) 1(B) * 1 / 2(C) * 1 / 6(D) 1/3?.
Solutions for 46. An aqueous solution containing KIO3 was treated with an excess of Kl solution. The solution is acidified with HCl. The liberated iodine consumed 10 ml of 0.1M thiosulphate solution to decolourises the starch iodine complex. Then millimoles of KIO3 consumed(A) 1(B) * 1 / 2(C) * 1 / 6(D) 1/3? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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