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When 5 equal point charges are placed at the corner of the regular hexagon electric field at the centre is e not if another charge is removed such that charges from two adjacent corners are missing the electric field at centre will be?
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When 5 equal point charges are placed at the corner of the regular hex...
Initial Configuration:
- In the initial configuration, 5 equal point charges are placed at the corners of a regular hexagon.
- The electric field at the center of the hexagon is denoted by E₀.

Effect of Removing Charges:
- If we remove a charge such that charges from two adjacent corners are missing, the electric field at the center will change.
- The electric field at the center will no longer be E₀, as the symmetry of the system is broken.
- The presence of the missing charges will create an imbalance in the distribution of charges, leading to a different electric field at the center.

Changes in Electric Field:
- The electric field at the center will now be influenced by the remaining charges and their relative positions.
- The magnitude and direction of the electric field will be different from the initial configuration.
- The electric field will be the vector sum of the electric fields due to the remaining charges.

Conclusion:
- In conclusion, removing two adjacent charges from the initial configuration of 5 equal point charges at the corners of a regular hexagon will change the electric field at the center.
- The new electric field will be determined by the remaining charges and their arrangement, resulting in a different magnitude and direction compared to the initial electric field E₀.
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When 5 equal point charges are placed at the corner of the regular hexagon electric field at the centre is e not if another charge is removed such that charges from two adjacent corners are missing the electric field at centre will be?
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