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"A one-time deposit of sum P has an interest rate of 5% per annum. If the sum amounts to 10,000 after 4 years, for how many more years will it need to be deposited in this particular bank so that it becomes 20,000?"?
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"A one-time deposit of sum P has an interest rate of 5% per annum. If ...



Calculating the number of years needed to reach 20,000

Given:

  • Principal amount (P) = sum deposited initially
  • Interest rate = 5% per annum
  • Amount after 4 years = 10,000


Calculating the future value of the principal amount after 4 years:

Using the formula for compound interest:

A = P(1 + r/100)^n

where A is the amount, P is the principal amount, r is the interest rate, and n is the number of years

Given that A = 10,000, P = P, r = 5%, and n = 4 years

10,000 = P(1 + 0.05)^4

10,000 = P(1.05)^4

Solving for P:

P = 10,000 / (1.05)^4

P ≈ 10,000 / 1.21550625

P ≈ 8,229.08

Calculating the number of years needed to reach 20,000:

Now, we need to find out how many more years it will take for the principal amount to double from 8,229.08 to 20,000.

Using the same formula for compound interest:

20,000 = 8,229.08(1 + 0.05)^n

Solving for n:

n = log(20,000 / 8,229.08) / log(1.05)

n ≈ log(2.43) / log(1.05)

n ≈ 9.79 years

Answer:

It will take approximately 9.79 more years for the amount to reach 20,000.


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"A one-time deposit of sum P has an interest rate of 5% per annum. If the sum amounts to 10,000 after 4 years, for how many more years will it need to be deposited in this particular bank so that it becomes 20,000?"?
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