Mechanical Engineering Exam > Mechanical Engineering Questions > A refrigerating machine working on reversed C...
Start Learning for Free
A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectively
- a)1 and 1 kW
- b)1 and 2 kW
- c)2 and 1 kW
- d)2 and 2 kW
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A refrigerating machine working on reversed Carnot cycle takes out 2 k...
COP = T2/(T1 - T2) = 200/(300-200) = 2 = Q/W
Given: Q = 2kW
Therefore, Power consumed by the cycle: W = Q/2 = 1kW
Most Upvoted Answer
A refrigerating machine working on reversed Carnot cycle takes out 2 k...
Reversed Carnot Cycle
The reversed Carnot cycle is a theoretical thermodynamic cycle that describes the most efficient way to convert heat into work. It consists of four processes:
1. Isothermal expansion
2. Adiabatic expansion
3. Isothermal compression
4. Adiabatic compression
COP (Coefficient of Performance)
The coefficient of performance (COP) is a measure of the efficiency of a refrigeration cycle. It is defined as the ratio of the heat removed from the system to the work input:
COP = Qc/W
where Qc is the heat removed from the system and W is the work input.
Power Consumption
Power consumption is the amount of energy consumed by a device per unit time. It is measured in watts (W) or kilowatts (kW).
Solution
Given:
Heat removed from the system (Qc) = 2 kW/min
Temperature limits:
High temperature (Th) = 300 K
Low temperature (Tc) = 200 K
To find:
COP and power consumption of the cycle
Using the formula for COP:
COP = Qc/W
We need to find W, the work input.
The reversed Carnot cycle is the most efficient cycle, so its COP is the highest possible for any refrigeration cycle operating between the same temperature limits.
The efficiency of the reversed Carnot cycle is given by:
efficiency = 1 - Tc/Th
Substituting the given values:
efficiency = 1 - 200/300 = 1/3
The efficiency is the ratio of the work output to the heat input:
efficiency = W/Qh
where Qh is the heat input.
We know that:
Qh - Qc = W
Substituting the given values:
Qh - 2 = W
Using the efficiency formula:
1/3 = W/Qh
Multiplying both sides by Qh:
Qh/3 = W
Substituting this value of W in the first equation:
Qh - 2 = Qh/3
Solving for Qh:
Qh = 6 kW/min
Now, we can find W:
W = Qh - Qc = 6 - 2 = 4 kW/min
Finally, we can find the COP:
COP = Qc/W = 2/4 = 0.5 = 2 (approx)
Since the COP is less than 1, it means that more work is required than the heat removed from the system. Therefore, the power consumption of the cycle is equal to the work input:
Power consumption = W = 4 kW/min
Therefore, the correct answer is option C: COP = 2 and power consumption = 1 kW.
The reversed Carnot cycle is a theoretical thermodynamic cycle that describes the most efficient way to convert heat into work. It consists of four processes:
1. Isothermal expansion
2. Adiabatic expansion
3. Isothermal compression
4. Adiabatic compression
COP (Coefficient of Performance)
The coefficient of performance (COP) is a measure of the efficiency of a refrigeration cycle. It is defined as the ratio of the heat removed from the system to the work input:
COP = Qc/W
where Qc is the heat removed from the system and W is the work input.
Power Consumption
Power consumption is the amount of energy consumed by a device per unit time. It is measured in watts (W) or kilowatts (kW).
Solution
Given:
Heat removed from the system (Qc) = 2 kW/min
Temperature limits:
High temperature (Th) = 300 K
Low temperature (Tc) = 200 K
To find:
COP and power consumption of the cycle
Using the formula for COP:
COP = Qc/W
We need to find W, the work input.
The reversed Carnot cycle is the most efficient cycle, so its COP is the highest possible for any refrigeration cycle operating between the same temperature limits.
The efficiency of the reversed Carnot cycle is given by:
efficiency = 1 - Tc/Th
Substituting the given values:
efficiency = 1 - 200/300 = 1/3
The efficiency is the ratio of the work output to the heat input:
efficiency = W/Qh
where Qh is the heat input.
We know that:
Qh - Qc = W
Substituting the given values:
Qh - 2 = W
Using the efficiency formula:
1/3 = W/Qh
Multiplying both sides by Qh:
Qh/3 = W
Substituting this value of W in the first equation:
Qh - 2 = Qh/3
Solving for Qh:
Qh = 6 kW/min
Now, we can find W:
W = Qh - Qc = 6 - 2 = 4 kW/min
Finally, we can find the COP:
COP = Qc/W = 2/4 = 0.5 = 2 (approx)
Since the COP is less than 1, it means that more work is required than the heat removed from the system. Therefore, the power consumption of the cycle is equal to the work input:
Power consumption = W = 4 kW/min
Therefore, the correct answer is option C: COP = 2 and power consumption = 1 kW.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer?
Question Description
A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer?.
A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A refrigerating machine working on reversed Carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200 K. COP and power consumption of the cycle will be respectivelya)1 and 1 kW b)1 and 2 kWc)2 and 1 kW d)2 and 2 kWCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup