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Find the least number which when divided by 6 15 and 18 leave remainder 5 in each case.?
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Find the least number which when divided by 6 15 and 18 leave remainde...
Finding the least number satisfying the given conditions
Finding a number that satisfies the given conditions involves finding the least common multiple (LCM) of the divisors and then adding the common remainder to it.

Step 1: Finding the LCM of 6, 15, and 18
- The prime factors of 6 are 2 and 3.
- The prime factors of 15 are 3 and 5.
- The prime factors of 18 are 2 and 3.
The LCM of 6, 15, and 18 is calculated by taking the highest power of each prime factor that appears in any of the numbers. Therefore, LCM(6, 15, 18) = 2^1 * 3^1 * 5^1 = 30.

Step 2: Adding the common remainder
Since the remainder in each case is 5, we add this common remainder to the LCM obtained in the previous step.
The least number that satisfies the given conditions is 30 + 5 = 35.
Therefore, the least number that when divided by 6, 15, and 18 leaves a remainder of 5 in each case is 35.
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