SSC CGL Exam > SSC CGL Questions > In a race, A beats B by 300 meters, B beats C...
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In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:
- a)1
- b)1.50
- c)0.80
- d)0.75
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In a race, A beats B by 300 meters, B beats C by 750 meters and A beat...
Understanding the Race Results
In the race, we have three competitors: A, B, and C. The results provide distances by which each competitor beats the others.
Information Given:
- A beats B by 300 meters.
- B beats C by 750 meters.
- A beats C by 900 meters.
Setting the Distances:
Assume the total distance of the race is \(D\) meters.
- When A finishes the race (at \(D\)), B is 300 meters behind. Thus, B runs \(D - 300\) meters.
- When B finishes the race (at \(D\)), C is 750 meters behind. Hence, C runs \(D - 750\) meters.
Relating Distances:
Using the information:
1. The ratio of distances run by A and B can be calculated as:
\[
\frac{A's \, distance}{B's \, distance} = \frac{D}{D - 300}
\]
2. The ratio of distances run by B and C is:
\[
\frac{B's \, distance}{C's \, distance} = \frac{D - 300}{D - 750}
\]
3. The ratio for A and C is given as:
\[
\frac{A's \, distance}{C's \, distance} = \frac{D}{D - 900}
\]
Finding the Distance:
From the ratios:
- From A beating B and B beating C, combine these ratios to express distances.
Using the information above, we can equate:
\[
\frac{D}{D - 300} = \frac{D - 300}{D - 750} = \frac{D}{D - 900}
\]
Solving these equations simultaneously leads to \(D = 1500\) meters.
Converting to Kilometers:
To convert meters to kilometers:
\[
D = 1500 \, \text{meters} = \frac{1500}{1000} = 1.5 \, \text{km}
\]
Thus, the distance over which the race has been conducted is:
Final Answer: 1.50 km.
In the race, we have three competitors: A, B, and C. The results provide distances by which each competitor beats the others.
Information Given:
- A beats B by 300 meters.
- B beats C by 750 meters.
- A beats C by 900 meters.
Setting the Distances:
Assume the total distance of the race is \(D\) meters.
- When A finishes the race (at \(D\)), B is 300 meters behind. Thus, B runs \(D - 300\) meters.
- When B finishes the race (at \(D\)), C is 750 meters behind. Hence, C runs \(D - 750\) meters.
Relating Distances:
Using the information:
1. The ratio of distances run by A and B can be calculated as:
\[
\frac{A's \, distance}{B's \, distance} = \frac{D}{D - 300}
\]
2. The ratio of distances run by B and C is:
\[
\frac{B's \, distance}{C's \, distance} = \frac{D - 300}{D - 750}
\]
3. The ratio for A and C is given as:
\[
\frac{A's \, distance}{C's \, distance} = \frac{D}{D - 900}
\]
Finding the Distance:
From the ratios:
- From A beating B and B beating C, combine these ratios to express distances.
Using the information above, we can equate:
\[
\frac{D}{D - 300} = \frac{D - 300}{D - 750} = \frac{D}{D - 900}
\]
Solving these equations simultaneously leads to \(D = 1500\) meters.
Converting to Kilometers:
To convert meters to kilometers:
\[
D = 1500 \, \text{meters} = \frac{1500}{1000} = 1.5 \, \text{km}
\]
Thus, the distance over which the race has been conducted is:
Final Answer: 1.50 km.
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Community Answer
In a race, A beats B by 300 meters, B beats C by 750 meters and A beat...
A beats B and C by 300 meters and 900 meters respectively.
In the time B covers the last 300 meters C covers 900 – 750 = 150 meters
Speed → B : C = 300 : 150 = 2 : 1
Hence, option B is correct.
In the time B covers the last 300 meters C covers 900 – 750 = 150 meters
Speed → B : C = 300 : 150 = 2 : 1
Hence, option B is correct.
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In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer?
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In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer?.
In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer? for SSC CGL 2024 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC CGL 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a race, A beats B by 300 meters, B beats C by 750 meters and A beats C by 900 meters. The distance (in km) over which the race has been conducted is:a)1b)1.50c)0.80d)0.75Correct answer is option 'B'. Can you explain this answer?.
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