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The sum of two-digit number and the number obtained by reversing it's digit is 121 find the number it is unit place digit is 5?
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The sum of two-digit number and the number obtained by reversing it's ...
Given Information:
The sum of a two-digit number and the number obtained by reversing its digits is 121. The unit's place digit of the number is 5.

Let's Solve the Problem:

Step 1: Represent the Number
Let the two-digit number be represented as 10a + 5, where 'a' represents the tens place digit.

Step 2: Reverse the Digits
The number obtained by reversing the digits is 10(5) + a = 50 + a.

Step 3: Form the Equation
According to the given information, the sum of the two-digit number and its reverse is 121:
(10a + 5) + (50 + a) = 121
Simplify the equation: 11a + 55 = 121
11a = 66
a = 6

Step 4: Find the Number
The two-digit number is 10a + 5 = 10(6) + 5 = 65

Step 5: Verify the Answer
Let's check if the number satisfies the given condition:
65 + 56 = 121
Therefore, the two-digit number with a unit's place digit of 5 is 65.
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The sum of two-digit number and the number obtained by reversing it's digit is 121 find the number it is unit place digit is 5?
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