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Q10: The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is , according to the herons formula:-?
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Q10: The area of an isosceles triangle having base 2 cm and the length...
Calculating the Area of an Isosceles Triangle using Heron's Formula:
1. Identify the Given Values:
- Base of the triangle (b) = 2 cm
- Length of one of the equal sides (a) = 4 cm
2. Calculate the Semi-Perimeter (s):
- Semi-perimeter (s) = (a + b + b) / 2
- s = (4 + 2 + 2) / 2
- s = 4
3. Calculate the Area using Heron's Formula:
- Area = √[s * (s - a) * (s - b) * (s - b)]
- Area = √[4 * (4 - 4) * (4 - 2) * (4 - 2)]
- Area = √[4 * 0 * 2 * 2]
- Area = √0
- Area = 0
4. Final Answer:
- The area of the isosceles triangle with a base of 2 cm and one equal side of 4 cm is 0 square cm.
In this case, the area of the triangle turns out to be 0 square cm because the given dimensions do not form a valid triangle. The semi-perimeter being equal to the base (s = 4) indicates that the triangle cannot exist in a Euclidean space. Thus, it is important to ensure the given dimensions satisfy the triangle inequality theorem before applying Heron's formula for accurate results.
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Q10: The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is , according to the herons formula:-?
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