Two identical metal spheres charged with +12μF and -8μF are ...
Analysis:
Initial Situation:
- The two identical metal spheres are initially charged with +12C and -8C, respectively.
- The electrostatic force between them can be calculated using Coulomb's law: F = k*q1*q2/r^2, where k is the Coulomb constant, q1 and q2 are the charges on the spheres, and r is the distance between them.
After Contact:
- When the spheres are brought into contact, charge transfer occurs until both spheres have the same charge (average of +12C and -8C, which is +2C each).
- The electrostatic force between the spheres after contact can be calculated using the same formula as above.
Ratio Calculation:
- The ratio of the magnitudes of electrostatic forces before and after contact can be found by comparing the expressions for F before and after contact.
- Let F1 be the force before contact and F2 be the force after contact.
- The ratio of F1 to F2 can be expressed as (k*q1*q2/r^2)/(k*q3*q4/r^2), where q3 and q4 are the charges on the spheres after contact.
Final Answer:
- Simplifying the ratio expression, we find that the ratio of the magnitudes of electrostatic forces before and after contact is 24:1.
Two identical metal spheres charged with +12μF and -8μF are ...
In first case f=k12*8/r^2 .....in 2nd case f'=k2*2/r^2( net charge =20+8/2=10....so 12micro c. give 10micro c. to 8 micro c. ) hence taking ratio it will be 24:1