Magnetism in [Cr(NH₃)₆]Cl₂

Explanation:

1. Octahedral Complex:
The compound [Cr(NH₃)₆]Cl₂ consists of a central chromium (Cr) ion surrounded by six ammonia (NH₃) ligands in an octahedral arrangement.

2. Chromium Ion:
The chromium ion in this complex has a d³ configuration, with three unpaired electrons in the d-orbitals.

3. Paramagnetic Behavior:
Due to the presence of unpaired electrons, [Cr(NH₃)₆]Cl₂ exhibits paramagnetic behavior. Paramagnetic substances are attracted to magnetic fields.

4. High Spin Complex:
The compound is classified as a high spin complex because the ligand field splitting energy is relatively low compared to the pairing energy, leading to the unpaired electrons occupying separate d-orbitals.

5. Magnetic Moment:
The magnetic moment of [Cr(NH₃)₆]Cl₂ can be calculated using the formula:
μ_eff = √(n(n+2))
Where n is the number of unpaired electrons. In this case, n = 3, so the effective magnetic moment is √(3(3+2)) = 3.87 BM (Bohr magnetons).

6. Overall Summary:
In summary, [Cr(NH₃)₆]Cl_{2 is a paramagnetic complex due to the presence of unpaired electrons on the chromium ion, leading to its attraction towards magnetic fields.}