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Vant hoff factor of Pt(NH3)2Cl2?
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Vant hoff factor of Pt(NH3)2Cl2?
Van't Hoff Factor of Pt(NH3)2Cl2

Explanation:
- The compound Pt(NH3)2Cl2 is a coordination complex consisting of platinum (Pt), ammonia (NH3), and chloride ions (Cl-).
- When this compound dissociates in solution, it breaks down into its ions.
- Each Pt(NH3)2Cl2 unit will dissociate into one Pt(NH3)2 2+ ion and two Cl- ions.
- Therefore, the total number of particles produced after dissociation is 3 (1 cation and 2 anions).
- The Van't Hoff factor (i) is a measure of the number of particles into which a compound dissociates in solution.
- In this case, the Van't Hoff factor for Pt(NH3)2Cl2 is 3.

Summary:
- The Van't Hoff factor of Pt(NH3)2Cl2 is 3 because it dissociates into one cation and two anions in solution.
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Vant hoff factor of Pt(NH3)2Cl2?
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