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If x = 2+root 3 find x3 + 1/x3
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If x = 2+root 3 find x3 + 1/x3?
Given:
x = 2 + √3

To Find:
x^3 + 1/x^3

Solution:

Step 1: Finding x^3
x^3 = (2 + √3)^3
Expanding using the formula (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
x^3 = 2^3 + 3*(2^2)*(√3) + 3*2*(√3)^2 + (√3)^3
x^3 = 8 + 12√3 + 18 + 3√3
x^3 = 26 + 15√3

Step 2: Finding 1/x^3
1/x^3 = 1/(26 + 15√3)
Multiplying numerator and denominator by the conjugate of the denominator to rationalize the denominator
1/x^3 = (26 - 15√3)/(26^2 - (15√3)^2)
1/x^3 = (26 - 15√3)/(676 - 675)
1/x^3 = (26 - 15√3)/1
1/x^3 = 26 - 15√3

Step 3: Final Calculation
x^3 + 1/x^3 = 26 + 15√3 + 26 - 15√3
x^3 + 1/x^3 = 52
Therefore, x^3 + 1/x^3 = 52
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