The work done against electric forces in increasing the potential diff...
Answer:
Given:
The initial potential difference of the capacitor = 20V
The final potential difference of the capacitor = 40V
Work done in increasing the potential difference from 20V to 40V = W
To find:
The work done in increasing the potential difference from 40V to 50V
Solution:
Work done in increasing the potential difference of a capacitor is given by:
W = ½ C (Vf² - Vi²)
Where,
C = capacitance of the capacitor
Vi = initial potential difference of the capacitor
Vf = final potential difference of the capacitor
Calculating the capacitance:
Capacitance of the capacitor is not given, hence we need to find it using the given values.
Let us assume that the capacitor has a capacitance of C farads.
Work done in increasing the potential difference from 20V to 40V:
W = ½ C (40² - 20²)
W = 600C
Work done in increasing the potential difference from 40V to 50V:
W' = ½ C (50² - 40²)
W' = 450C
Answer:
The work done in increasing the potential difference from 40V to 50V is 450C.