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The work done against electric forces in increasing the potential difference of a condenser from 20V to 40V is W. The work done in increasing its potential difference from 40V to 50V will be?
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The work done against electric forces in increasing the potential diff...
W/2.Because W=Q∆V.So in first case ∆V is 20 And in the second case ∆V is 10.Divide 1 and 2 equation to receive your answer.....
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The work done against electric forces in increasing the potential diff...
Answer:


Given:

The initial potential difference of the capacitor = 20V

The final potential difference of the capacitor = 40V

Work done in increasing the potential difference from 20V to 40V = W


To find:

The work done in increasing the potential difference from 40V to 50V


Solution:


Work done in increasing the potential difference of a capacitor is given by:

W = ½ C (Vf² - Vi²)


Where,

C = capacitance of the capacitor

Vi = initial potential difference of the capacitor

Vf = final potential difference of the capacitor


Calculating the capacitance:

Capacitance of the capacitor is not given, hence we need to find it using the given values.

Let us assume that the capacitor has a capacitance of C farads.


Work done in increasing the potential difference from 20V to 40V:

W = ½ C (40² - 20²)

W = 600C


Work done in increasing the potential difference from 40V to 50V:

W' = ½ C (50² - 40²)

W' = 450C


Answer:

The work done in increasing the potential difference from 40V to 50V is 450C.
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The work done against electric forces in increasing the potential difference of a condenser from 20V to 40V is W. The work done in increasing its potential difference from 40V to 50V will be?
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