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Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.

  • a)
    0.1 N along the direction of motion

  • b)
    0.2 opposite to the direction of motion

  • c)
    0.1 N opposite to the direction of motion

  • d)
    1.0 N in the direction of motion

Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Give the magnitude and direction of the net force acting on a stone of...
To determine the magnitude and direction of the net force acting on the stone, we need to consider the forces acting on it.

1. Weight (Gravity): The stone has a mass of 0.1 kg, so its weight is given by W = mg, where g is the acceleration due to gravity (approximately 9.8 m/s²). Therefore, the weight of the stone is W = 0.1 kg × 9.8 m/s² = 0.98 N. The direction of the weight is vertically downward.

2. Normal Force: Since the stone is lying on the floor of the train, the floor exerts an equal and opposite force called the normal force to support the stone. The normal force balances the weight of the stone, so its magnitude is also 0.98 N. The direction of the normal force is vertically upward.

3. Net Force: The net force acting on the stone is the vector sum of all the forces acting on it. In this case, the net force is the difference between the weight and the normal force, since they act in opposite directions. Therefore, the magnitude of the net force is:

Net Force = Weight - Normal Force
Net Force = 0.98 N - 0.98 N
Net Force = 0 N

The net force acting on the stone is zero. This means that the stone is in a state of equilibrium, with the gravitational force and the normal force canceling each other out.
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Give the magnitude and direction of the net force acting on a stone of...
Key points:



  • The stone has a mass of 0.1 kg.

  • The train is moving at a constant velocity (1 m/s).

  • The stone is at rest relative to the train.

  • We are neglecting air resistance.



Since the stone is at rest relative to the train and the train is moving with a constant accleration, the net force acting on mass .

F= ma 

F =0.1 x 1 N

F = 0.1 N
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Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.a)0.1 N along thedirection of motionb)0.2 opposite to the direction of motionc)0.1 N opposite to the direction of motiond)1.0 N in the direction of motionCorrect answer is option 'A'. Can you explain this answer? for Class 11 2026 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.a)0.1 N along thedirection of motionb)0.2 opposite to the direction of motionc)0.1 N opposite to the direction of motiond)1.0 N in the direction of motionCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.a)0.1 N along thedirection of motionb)0.2 opposite to the direction of motionc)0.1 N opposite to the direction of motiond)1.0 N in the direction of motionCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.a)0.1 N along thedirection of motionb)0.2 opposite to the direction of motionc)0.1 N opposite to the direction of motiond)1.0 N in the direction of motionCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
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