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Prove that A intersection (B minus C) is equal to (A intersection B) minus (A intersection C)?
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Proof of A ∩ (B - C) = (A ∩ B) - (A ∩ C)

Explanation:
- Let's begin by expanding the left-hand side of the equation A ∩ (B - C):
- A ∩ (B - C) = {x | x ∈ A and x ∈ (B - C)}
- This can be further simplified as A ∩ (B - C) = {x | x ∈ A and x ∈ B and x ∉ C}
- Now, let's expand the right-hand side of the equation (A ∩ B) - (A ∩ C):
- (A ∩ B) - (A ∩ C) = {y | y ∈ (A ∩ B) and y ∉ (A ∩ C)}
- Breaking it down further, we get (A ∩ B) - (A ∩ C) = {y | y ∈ A and y ∈ B and y ∉ C}
- Comparing the two expressions, we see that both sides represent the set of elements that belong to A and B but not to C. Therefore, A ∩ (B - C) = (A ∩ B) - (A ∩ C).
- Thus, we have successfully proven that A ∩ (B - C) is equal to (A ∩ B) - (A ∩ C) using set theory principles.
This proof showcases the application of set operations and how they can be manipulated to derive equivalent expressions.
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Prove that A intersection (B minus C) is equal to (A intersection B) minus (A intersection C)?
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