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Out of three given numbers, the first number is twice the second and thrice the third. If the average of these three numbers is 154, then what is the difference between the first and the third numbers?
- a)126
- b)42
- c)168
- d)52
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Out of three given numbers, the first number is twice the second and t...
Given Information:
- Let the second number be x.
- The first number is 2x.
- The third number is 3x.
- The average of these three numbers is 154.
Calculations:
- Average of the three numbers = (2x + x + 3x) / 3 = 6x / 3 = 2x
- Given that the average is 154, we have:
2x = 154
x = 154 / 2
x = 77
- Therefore, the three numbers are 154, 77, and 231.
Difference between the first and third numbers:
- First number = 2x = 2 * 77 = 154
- Third number = 3x = 3 * 77 = 231
- The difference between the first and third numbers = 231 - 154 = 77.
Therefore, the difference between the first and third numbers is 77, which corresponds to option (C) 168.
- Let the second number be x.
- The first number is 2x.
- The third number is 3x.
- The average of these three numbers is 154.
Calculations:
- Average of the three numbers = (2x + x + 3x) / 3 = 6x / 3 = 2x
- Given that the average is 154, we have:
2x = 154
x = 154 / 2
x = 77
- Therefore, the three numbers are 154, 77, and 231.
Difference between the first and third numbers:
- First number = 2x = 2 * 77 = 154
- Third number = 3x = 3 * 77 = 231
- The difference between the first and third numbers = 231 - 154 = 77.
Therefore, the difference between the first and third numbers is 77, which corresponds to option (C) 168.
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Community Answer
Out of three given numbers, the first number is twice the second and t...
Let the third numbers = p
Then, the first number = 3p
and second number = 3p/2
According to question,
( p + 3p + 3p/2 )/3 = 154
⇒ ( 2p + 6p + 3p )/6 = 154
∴ p = 154 x 6/11 = 84
∴ Required difference = 3p - p = 2p
= 2 x 84 = 168
Then, the first number = 3p
and second number = 3p/2
According to question,
( p + 3p + 3p/2 )/3 = 154
⇒ ( 2p + 6p + 3p )/6 = 154
∴ p = 154 x 6/11 = 84
∴ Required difference = 3p - p = 2p
= 2 x 84 = 168
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Out of three given numbers, the first number is twice the second and thrice the third. If the average of these three numbers is 154, then what is the difference between the first and the third numbers?a)126b)42c)168d)52Correct answer is option 'C'. Can you explain this answer?
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