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Two infinitely long parallel conducting plates having surface charge densities +σ and -σ respectively, are separated by a small distance. The medium between the plates is vacuum. If ε₀ is the dielectric permittvity of vacuum, then electric field in the region between the plates is
  • a)
    0 V−m-1
  • b)
    σ/ε₀ V-m-1
  • c)
    σ/2ε₀ V-m-1
  • d)
    2σ/ε₀ V-m-1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two infinitely long parallel conducting plates having surface charge d...
Electric Field Calculation between Parallel Plates
The electric field between the parallel plates can be calculated using the formula:
E = σ / ε

Explanation:
- The electric field between the plates is uniform and directed from the positive plate to the negative plate.
- The electric field due to the positive plate is E = σ / (2ε) and due to the negative plate is E = -σ / (2ε).
- The net electric field between the plates is the sum of the electric fields due to both plates, which results in E = σ / ε.
Therefore, the correct answer is option 'b' - σ / ε V-m-1.
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Two infinitely long parallel conducting plates having surface charge densities +σ and -σ respectively, are separated by a small distance. The medium between the plates is vacuum. If ε is the dielectric permittvity of vacuum, then electric field in the region between the plates isa)0 V−m-1b)σ/ε V-m-1c)σ/2ε V-m-1d)2σ/ε V-m-1Correct answer is option 'B'. Can you explain this answer?
Question Description
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