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What amount of energy is released in the fission of 95U235 ?
- a)200 keV
- b)20 eV
- c)200 eV
- d)200 MeV
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What amount of energy is released in the fission of95U235?a)200...
The fission process represented by the equation, 92U235+0n1→56Ba144+36Kr89+30n1
Masses of reactants =234.39+1.01=235.4amu
Masses of products =143.28+88.89+3(1.01) =235.2amu
Energy released = mass difference =235.4−235.2=0.2amu=0.2×931∼200MeV
Masses of reactants =234.39+1.01=235.4amu
Masses of products =143.28+88.89+3(1.01) =235.2amu
Energy released = mass difference =235.4−235.2=0.2amu=0.2×931∼200MeV
Most Upvoted Answer
What amount of energy is released in the fission of95U235?a)200...
Around 200 MeV energy is released per fission. The exact value however depends on the fission products. Around 200 fission products have been identified. For calculation, exact equation(fission reaction) is required.
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What amount of energy is released in the fission of95U235?a)200...
You just have to remember that it is about 200Mev. No other option. Thanks
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