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The floor of a rectangular hall has been decorated by a rectangular carpet having its two adjacent sides as 7a^2 +14ab +6b^2 and 3a^2- 9ab+4b^2?
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The floor of a rectangular hall has been decorated by a rectangular ca...
Explanation of the Decorated Rectangular Hall
The rectangular hall has been decorated by a rectangular carpet with dimensions given as:
- Length: 7a^2 + 14ab + 6b^2
- Width: 3a^2 - 9ab + 4b^2

Area of the Carpet
To find the area of the carpet, we multiply the length by the width:
Area = Length x Width
Area = (7a^2 + 14ab + 6b^2) x (3a^2 - 9ab + 4b^2)
Area = 21a^4 - 63a^3b + 28a^2b^2 + 42a^3b - 126a^2b^2 + 56ab^3 + 18a^2b^2 - 54ab^3 + 24b^4
Area = 21a^4 - 21a^3b - 60a^2b^2 - 78ab^3 + 24b^4

Explanation of the Area
The resulting area of the carpet is a polynomial expression in terms of a and b. The area represents the total surface covered by the carpet on the floor of the rectangular hall.

Conclusion
The rectangular hall has been decorated with a carpet whose area is given by the polynomial expression: 21a^4 - 21a^3b - 60a^2b^2 - 78ab^3 + 24b^4. This area provides an aesthetically pleasing and functional addition to the hall's decor.
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The floor of a rectangular hall has been decorated by a rectangular carpet having its two adjacent sides as 7a^2 +14ab +6b^2 and 3a^2- 9ab+4b^2?
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