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A small steam whistle (perfectly insulated and doing no shaft work) causes a drop of 0.8 kJ/kg in enthalpy of steam from entry to exit. The kinetic energy of the steam at entry is negligible, the velocity of steam at exit is
  • a)
    4 m/s
  • b)
    40 m/s
  • c)
    80 m/s
  • d)
    120 m/s
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A small steam whistle (perfectly insulated and doing no shaft work) ca...
Given data:
- Enthalpy drop of steam = 0.8 kJ/kg
- Kinetic energy at entry = negligible

Calculating the exit velocity:
- The enthalpy drop is due to the conversion of internal energy to kinetic energy at the exit.
- The enthalpy drop is equal to the increase in kinetic energy.
- We can use the equation: h1 - h2 = V2^2/2 - V1^2/2
- Given h1 - h2 = 0.8 kJ/kg and V1 = 0 m/s (negligible), we can solve for V2.

Solving for the exit velocity:
0.8 = V2^2/2 - 0
V2^2 = 2 * 0.8
V2 = sqrt(1.6) = 1.26 m/s

Answer:
- The exit velocity of steam is approximately 1.26 m/s.
- Among the given options, the closest answer is 40 m/s (option B).
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A small steam whistle (perfectly insulated and doing no shaft work) ca...
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