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Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:
- a)Sphere of radius R1 will have greater potential
- b)Sphere of radius R2 will have greater potential
- c)Potential of both the spheres will be equal
- d)Sphere of radius R1 will have zero potential
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Two spheres of radii R1 and R2 (R2 > R1) are connected by a conduct...
Understanding Charge Distribution and Potential
When two conducting spheres are connected by a wire, charge redistributes between them until they reach the same electric potential.
Key Concepts:
- Conductors and Electric Potential:
- Conductors allow free movement of charge. When connected, they equalize their potentials.
- Relation of Charge, Radius, and Potential:
- The electric potential (V) of a sphere is given by V = k * Q/R, where Q is the charge, R is the radius, and k is a constant.
- For two spheres with the same charge q, the potentials would be:
- V1 = k * q / R1 for sphere 1
- V2 = k * q / R2 for sphere 2
Equilibrium of Potential:
- Since R2 > R1, initially, V1 (potential of smaller sphere) would be greater than V2 (potential of larger sphere) due to the inverse relationship between potential and radius.
- Once the spheres are connected, charge flows until V1 = V2. This occurs because the charge will redistribute in such a way that both spheres attain the same potential.
Conclusion:
- Therefore, the final potential of both spheres will be equal when they are connected by a conducting wire, leading to the correct answer being option 'C'.
In summary, the connection allows for charge redistribution, ensuring both spheres maintain the same electric potential despite their different sizes.
When two conducting spheres are connected by a wire, charge redistributes between them until they reach the same electric potential.
Key Concepts:
- Conductors and Electric Potential:
- Conductors allow free movement of charge. When connected, they equalize their potentials.
- Relation of Charge, Radius, and Potential:
- The electric potential (V) of a sphere is given by V = k * Q/R, where Q is the charge, R is the radius, and k is a constant.
- For two spheres with the same charge q, the potentials would be:
- V1 = k * q / R1 for sphere 1
- V2 = k * q / R2 for sphere 2
Equilibrium of Potential:
- Since R2 > R1, initially, V1 (potential of smaller sphere) would be greater than V2 (potential of larger sphere) due to the inverse relationship between potential and radius.
- Once the spheres are connected, charge flows until V1 = V2. This occurs because the charge will redistribute in such a way that both spheres attain the same potential.
Conclusion:
- Therefore, the final potential of both spheres will be equal when they are connected by a conducting wire, leading to the correct answer being option 'C'.
In summary, the connection allows for charge redistribution, ensuring both spheres maintain the same electric potential despite their different sizes.
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Community Answer
Two spheres of radii R1 and R2 (R2 > R1) are connected by a conduct...
Concept:
Flowing of charge does not depend upon the charge amount or size of the two bodies.
If there is an electric potential difference there will be a flow of charge, if no potential difference, there will not be a flow of charge i.e. current flow is not possible.
Thus, in all electrical circuits when the current flows, it means there is an electrical potential difference between two points.
Application:
Two spheres of radii R
1
and R2
(R2
> R1
) are connected by a conducting wire. Each of the spheres has been given a charge q.Now
Potential of both the spheres will be equal
because of both sphere has the same charge.Attention Mechanical Engineering Students!
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Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:a)Sphere of radius R1 will have greater potentialb)Sphere of radius R2 will have greater potentialc)Potential of both the spheres will be equald)Sphere of radius R1 will have zero potentialCorrect answer is option 'C'. Can you explain this answer?
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Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:a)Sphere of radius R1 will have greater potentialb)Sphere of radius R2 will have greater potentialc)Potential of both the spheres will be equald)Sphere of radius R1 will have zero potentialCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:a)Sphere of radius R1 will have greater potentialb)Sphere of radius R2 will have greater potentialc)Potential of both the spheres will be equald)Sphere of radius R1 will have zero potentialCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:a)Sphere of radius R1 will have greater potentialb)Sphere of radius R2 will have greater potentialc)Potential of both the spheres will be equald)Sphere of radius R1 will have zero potentialCorrect answer is option 'C'. Can you explain this answer?.
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ample number of questions to practice Two spheres of radii R1 and R2 (R2 > R1) are connected by a conducting wire. Each of the spheres has been given a charge q. Now:a)Sphere of radius R1 will have greater potentialb)Sphere of radius R2 will have greater potentialc)Potential of both the spheres will be equald)Sphere of radius R1 will have zero potentialCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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