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Two balls of equal mass and of Perfectly inelastic material are lying on the floor. One of the balls with velocity V is made to strike the second ball. Both the balls after impact will move with a velocity

  • a)
    v

  • b)
    v/8

  • c)
    v/4

  • d)
    v/2

Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two balls of equal mass and of Perfectly inelastic material are lying ...
Given:


Let two balls A and B have mass mA, mB respectively, and their initial velocities are uA and uB. After the collision, they will move with the same velocity, vo


Given that mass of both balls are same.


So  mA = mB = m


uA = V,  uB = 0


From the Concept of Momentum Conservation:


mAuA + mBuB = (m+m)vo


mV = 2mvo


vo = V/2


Both the balls after impact will move with velocity v/2.
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Community Answer
Two balls of equal mass and of Perfectly inelastic material are lying ...
Given:
- Largest numerical value = 85
- Smallest numerical value = 65
- Number of desired classes = 8

To find:
- Width of class interval

Solution:
Step 1: Find the range
- Range = Largest value - Smallest value
- Range = 85 - 65
- Range = 20

Step 2: Determine the class interval
- Class interval = Range / Number of desired classes
- Class interval = 20 / 8
- Class interval = 2.5

Therefore, the width of class interval is 2.5.

Note: Option D is the correct answer.
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