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In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to where one of the following inter-orbit jumps of electron for Bohr orbits in an atom of hydrogen.                [AIEEE- 2003]
  • a)
    4 → 1
  • b)
    2 → 5 
  • c)
    3 → 2
  • d)
    5 → 2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In Bohr series of lines of hydrogen spectrum, third line from the red ...
The answer is d.
The electron has minimum energy in the first orbit and its energy increases as n increases. Here n represents number of orbit, i.e. 1st, 2nd, 3rd .... The third line from the red end corresponds to yellow region i.e. 5. In order to obtain less energy electron tends to come in 1st or 2nd orbit. So jump may be involved either 5 → 1 or 5 → 2.
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Most Upvoted Answer
In Bohr series of lines of hydrogen spectrum, third line from the red ...
Here red end is written which means visible region I.e.balmer series and third line will be 5 to 2 ans is d I think
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Community Answer
In Bohr series of lines of hydrogen spectrum, third line from the red ...
The third line from the red end corresponds to the jump from the 4th energy level (n=4) to the 2nd energy level (n=2) in the Bohr model of the hydrogen atom.
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In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to where one of the following inter-orbit jumps of electron for Bohr orbits in an atom of hydrogen. [AIEEE- 2003]a)4 →1b)2 →5c)3 →2d)5 →2Correct answer is option 'B'. Can you explain this answer?
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