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A car is dropped from a height of 0.5 m in 1 second find the velocity of car before collision and the force applied if the mass of caris 1200 kg?
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A car is dropped from a height of 0.5 m in 1 second find the velocity ...
Calculation of Velocity Before Collision
To determine the velocity of the car just before it hits the ground, we can use the formula for velocity under free fall:
- **Formula:**
\( v = u + gt \)
Where:
- \( v \) = final velocity
- \( u \) = initial velocity (0 m/s, since the car is dropped)
- \( g \) = acceleration due to gravity (approximately \( 9.81 m/s^2 \))
- \( t \) = time of fall (1 second)
- **Calculation:**
- Since \( u = 0 \):
\( v = 0 + (9.81 \, \text{m/s}^2)(1 \, \text{s}) \)
\( v = 9.81 \, \text{m/s} \)

Force Applied Before Collision
Next, we can calculate the force applied just before the car collides with the ground using Newton's second law of motion:
- **Formula:**
\( F = ma \)
Where:
- \( F \) = force
- \( m \) = mass of the car (1200 kg)
- \( a \) = acceleration (in this case, it is \( g \), the acceleration due to gravity)
- **Calculation:**
- \( F = 1200 \, \text{kg} \times 9.81 \, \text{m/s}^2 \)
- \( F = 11772 \, \text{N} \)

Summary of Results
- **Velocity before collision:**
- \( 9.81 \, \text{m/s} \)
- **Force applied during the fall:**
- \( 11772 \, \text{N} \)
This provides a clear understanding of the car's velocity just before impact and the force exerted due to gravity.
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