All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  A cylinder of mass 1kg given heat of 20000 at... Start Learning for Free
SaveJoin the Discussion on the App
A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder?
Clear all your JEE doubts with EduRev
Most Upvoted Answer
A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if ...
Can any body answered fast
Explore Courses for JEE exam

Similar JEE Doubts

The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. The value of theoretical lapse rate on the earth is (use g = 9.8 m/s2 ; R = 8.3 J/mol-k and M = 29 g/mol)

The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to . Assuming free fall acceleration to be uniform, then lapse rate is given by

The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. If behaviour of the mixing of parcels of air is approximately assumed to be adiabatic then lapse rate can be expressed as

Top Courses for JEEView all

Top Courses for JEE

A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder?
Question Description
A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder?.
Solutions for A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? defined & explained in the simplest way possible. Besides giving the explanation of A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder?, a detailed solution for A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? has been provided alongside types of A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? theory, EduRev gives you an ample number of questions to practice A cylinder of mass 1kg given heat of 20000 at atmospheric pressure if intially the temperature of cylinder is 20C find (s=400, density=9000kg/m^3 densityat0c =10^5 , volume expansion=9×10^-5). a.final temperature b.workdone by cylinder c.change in internal energy of cylinder? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup