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A bar of diameter 30 mm is subjected to a tensile load such that the measured extension on a gauge length of 200 mm is 0.09 mm and the change in diameter is 0.0045 mm. The poisson’s ratio will be
  • a)
    1/4
  • b)
    1/3
  • c)
    1/5
  • d)
    1/6
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A bar of diameter 30 mm is subjected to a tensile load such that the m...
Longitudinal strain = 0.09/200
Lateral strain = – 0.0045/30
Poissons ratio = – lateral strain/ longitudinal strain
= 0.0045/30 x 200/0.09
= 1/3.
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Most Upvoted Answer
A bar of diameter 30 mm is subjected to a tensile load such that the m...
's ratio for the material is not given. Without knowing the Poisson's ratio, it is not possible to calculate the final answer. Poisson's ratio is needed to determine the change in diameter due to the tensile load.
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A bar of diameter 30 mm is subjected to a tensile load such that the measured extension on a gauge length of 200 mm is 0.09 mm and the change in diameter is 0.0045 mm. The poisson’s ratio will bea)1/4b)1/3c)1/5d)1/6Correct answer is option 'B'. Can you explain this answer?
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