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Pre weighed vessel was filled with oxygen at N.T.P. and weighted.It was then evacuated, filled with
S
O
2
at the same temperature and pressure, and again weighed. The weight of oxygen will be?
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Pre weighed vessel was filled with oxygen at N.T.P. and weighted.It wa...
Understanding the Experiment
In this experiment, we are evaluating the weight of oxygen (O₂) filled in a pre-weighed vessel at Normal Temperature and Pressure (N.T.P.) and then replacing it with sulfur dioxide (SO₂) after evacuation.
Key Concepts
- N.T.P. Conditions: Normal Temperature and Pressure is defined as 0°C (273.15 K) and 1 atm pressure. Under these conditions, the molar volumes of gases are standardized.
- Molar Masses:
- Oxygen (O₂) has a molar mass of approximately 32 g/mol.
- Sulfur Dioxide (SO₂) has a molar mass of approximately 64 g/mol.
Weight Determination
- When the vessel is filled with O₂ at N.T.P., the weight can be calculated using the ideal gas law. The number of moles of O₂ can be determined based on the molar volume (22.4 L/mol at N.T.P.).
- After the vessel is evacuated and filled with SO₂, the weight change can be determined by the difference in weight before and after filling.
Weight Calculation
- Let the volume of the vessel be V liters.
- The weight of oxygen can be calculated as:
- Weight of O₂ = (Molar mass of O₂) × (Number of moles of O₂)
- Number of moles of O₂ = Volume (V) / Molar volume (22.4 L)
- Therefore, Weight of O₂ = (32 g/mol) × (V / 22.4 L)
- After filling with SO₂, the weight would change similarly based on the molar mass of SO₂.
Conclusion
- By knowing the volume of the vessel and the molar mass of O₂, we can accurately determine the weight of oxygen initially filled in the vessel. This approach highlights the relationship between gas properties and molar mass at standardized conditions.
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Pre weighed vessel was filled with oxygen at N.T.P. and weighted.It was then evacuated, filled with SO2 at the same temperature and pressure, and again weighed. The weight of oxygen will be?
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