If 2 L of Cl2 gas and 2 L of ClF3 gas react to form 6 L of a pure gaseous compound at the same conditions of temperature and pressure, what is the molecular formula of the compound formed?a)ClFb)Cl2F2c)Cl3F3d)Cl2F3Correct answer is option 'C'. Can you explain this answer?

Question

Answer

A is the correct ans

Answer

Answer is C

Answer

Answer c

Answer

To determine the molecular formula of the compound formed when 2 L of Cl2 gas and 2 L of ClF3 gas react to form 6 L of a pure gaseous compound, we need to analyze the reactants and products involved in the reaction.

Reactants:
- 2 L of Cl2 gas
- 2 L of ClF3 gas

Product:
- 6 L of a pure gaseous compound

The reaction equation can be represented as follows:
2 Cl2 (g) + 2 ClF3 (g) → 6 X (g)

From the reaction equation, we can deduce the following:

1. Conservation of Mass:
Since the total volume of the reactants is 4 L (2 L Cl2 + 2 L ClF3) and the total volume of the product is 6 L, we can conclude that the reaction is not accompanied by any change in pressure or temperature. Therefore, the total number of moles of gas must be conserved.

2. Stoichiometry:
Since the ratio of Cl2 to ClF3 in the reactants is 1:1, we can deduce that the product must contain both chlorine and fluorine in equal proportions.

Now, let's analyze the possible molecular formulas for the compound formed:

a) ClF: This compound does not satisfy the stoichiometry requirement, as it contains only one chlorine atom and one fluorine atom.

b) Cl2F2: This compound also does not satisfy the stoichiometry requirement, as it contains two chlorine atoms and two fluorine atoms.

c) Cl3F3: This compound satisfies the stoichiometry requirement, as it contains three chlorine atoms and three fluorine atoms. The balanced equation for the reaction would be:
2 Cl2 (g) + 2 ClF3 (g) → 6 Cl3F3 (g)

d) Cl2F3: This compound does not satisfy the stoichiometry requirement, as it contains two chlorine atoms and three fluorine atoms.

Therefore, the correct molecular formula for the compound formed is Cl3F3 (option C).

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