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A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car?
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A car is moving with the uniform acceleration. It's velocity increases...
Understanding the Problem
The car is moving with uniform acceleration, meaning that its speed increases at a constant rate. We need to find the acceleration given:
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 30 m/s
- Distance (s) = 200 m
Using the Kinematic Equation
To find acceleration (a), we can use the kinematic equation:
v² = u² + 2as
Where:
- v = final velocity
- u = initial velocity
- a = acceleration
- s = distance
Calculating the Acceleration
1. Substituting the Known Values:
- v² = (30 m/s)² = 900 m²/s²
- u² = (10 m/s)² = 100 m²/s²
- s = 200 m
2. Rearranging the Equation:
- 900 = 100 + 2a(200)
3. Solving for a:
- 900 - 100 = 2a(200)
- 800 = 400a
- a = 800 / 400
- a = 2 m/s²
Final Result
The acceleration of the car is 2 m/s².
Conclusion
Understanding how to use kinematic equations allows us to solve problems involving motion and acceleration effectively. Always remember to isolate the variable you need to find, and substitute known values carefully.
The car is moving with uniform acceleration, meaning that its speed increases at a constant rate. We need to find the acceleration given:
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 30 m/s
- Distance (s) = 200 m
Using the Kinematic Equation
To find acceleration (a), we can use the kinematic equation:
v² = u² + 2as
Where:
- v = final velocity
- u = initial velocity
- a = acceleration
- s = distance
Calculating the Acceleration
1. Substituting the Known Values:
- v² = (30 m/s)² = 900 m²/s²
- u² = (10 m/s)² = 100 m²/s²
- s = 200 m
2. Rearranging the Equation:
- 900 = 100 + 2a(200)
3. Solving for a:
- 900 - 100 = 2a(200)
- 800 = 400a
- a = 800 / 400
- a = 2 m/s²
Final Result
The acceleration of the car is 2 m/s².
Conclusion
Understanding how to use kinematic equations allows us to solve problems involving motion and acceleration effectively. Always remember to isolate the variable you need to find, and substitute known values carefully.
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A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car?
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A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car?.
A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving with the uniform acceleration. It's velocity increases from 10 m per second to 30 m per second over a distance of 200 m. What is the acceleration of the car?.
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