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A cheetah can accelerate from rest at the rate of 4m/s find
.a) what will be the velocity attained by in 10 secs
b.) how far will it travel in this duration?
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A cheetah can accelerate from rest at the rate of 4m/s find .a) what w...
Acceleration of a Cheetah
The acceleration of the cheetah is given as 4 m/s². We will determine the velocity attained after 10 seconds and the distance traveled in that time.
Part A: Velocity Attained After 10 Seconds
- Formula: The formula to calculate final velocity (v) when starting from rest is:
- v = u + at
- Where:
- u = initial velocity (0 m/s)
- a = acceleration (4 m/s²)
- t = time (10 s)
- Calculation:
- v = 0 + (4 m/s² * 10 s)
- v = 40 m/s
- Conclusion:
- The cheetah will attain a velocity of 40 m/s after 10 seconds.
Part B: Distance Traveled in 10 Seconds
- Formula: The formula to calculate distance (s) when starting from rest is:
- s = ut + (1/2)at²
- Where:
- u = initial velocity (0 m/s)
- a = acceleration (4 m/s²)
- t = time (10 s)
- Calculation:
- s = (0 * 10) + (1/2 * 4 m/s² * (10 s)²)
- s = 0 + (2 * 100)
- s = 200 m
- Conclusion:
- The cheetah will travel a distance of 200 meters in 10 seconds.
In summary, after 10 seconds, the cheetah achieves a velocity of 40 m/s and covers a distance of 200 meters.
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A cheetah can accelerate from rest at the rate of 4m/s find .a) what will be the velocity attained by in 10 secs b.) how far will it travel in this duration?
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A cheetah can accelerate from rest at the rate of 4m/s find .a) what will be the velocity attained by in 10 secs b.) how far will it travel in this duration? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A cheetah can accelerate from rest at the rate of 4m/s find .a) what will be the velocity attained by in 10 secs b.) how far will it travel in this duration? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cheetah can accelerate from rest at the rate of 4m/s find .a) what will be the velocity attained by in 10 secs b.) how far will it travel in this duration?.
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