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The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle.
- a)280 m
- b)320 m2
- c)240 m2
- d)300 m2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The ratio of the perimeter of the square to the perimeter of a rectang...
Let the side of the square be 's'.
The perimeter of the square/ The perimeter of the rectangle = 1/1
4 * side of square/ 2 * (length + breadth) = 1/1
2 * s/ (20 + 3s/4) = 1/1
2s = 20 + 3s/4
(8s - 3s)/ 4 = 20
5s = 20 * 4
s = 16 m
breadth = 16 * 3/4 = 12 m
Hence, the area of rectangle = length * breadth = 20 * 12
= 240 m2
Most Upvoted Answer
The ratio of the perimeter of the square to the perimeter of a rectang...
Understanding the Problem
We know that the ratio of the perimeter of a square to the perimeter of a rectangle is 1:1. We also have the following information:
- The breadth of the rectangle is 3/4 times the side of the square.
- The length of the rectangle is 20 m.
Step 1: Finding the Perimeter of the Square
Let the side of the square be "s".
- The perimeter of the square = 4 * s.
Step 2: Finding the Perimeter of the Rectangle
The perimeter of the rectangle can be calculated as:
- Perimeter of the rectangle = 2 * (length + breadth).
- Given: Length = 20 m and breadth = (3/4) * s.
Thus, the perimeter of the rectangle becomes:
- Perimeter of the rectangle = 2 * (20 + (3/4)s).
Step 3: Setting the Perimeters Equal
Since the perimeters are equal, we can set them up as follows:
- 4s = 2 * (20 + (3/4)s).
Step 4: Solving for s
Simplifying the equation:
- 4s = 40 + (3/2)s.
- Bringing all terms with "s" on one side gives us:
- 4s - (3/2)s = 40.
- Converting 4s to a fraction:
- (8/2)s - (3/2)s = 40.
- (5/2)s = 40.
- Therefore, s = 40 * (2/5) = 16 m.
Step 5: Finding the Breadth
Now, calculate the breadth:
- Breadth = (3/4) * s = (3/4) * 16 = 12 m.
Step 6: Calculating the Area of the Rectangle
Finally, the area of the rectangle can be calculated as:
- Area = Length * Breadth = 20 m * 12 m = 240 m².
Conclusion
Thus, the area of the rectangle is 240 m², and the correct answer is option 'c'.
We know that the ratio of the perimeter of a square to the perimeter of a rectangle is 1:1. We also have the following information:
- The breadth of the rectangle is 3/4 times the side of the square.
- The length of the rectangle is 20 m.
Step 1: Finding the Perimeter of the Square
Let the side of the square be "s".
- The perimeter of the square = 4 * s.
Step 2: Finding the Perimeter of the Rectangle
The perimeter of the rectangle can be calculated as:
- Perimeter of the rectangle = 2 * (length + breadth).
- Given: Length = 20 m and breadth = (3/4) * s.
Thus, the perimeter of the rectangle becomes:
- Perimeter of the rectangle = 2 * (20 + (3/4)s).
Step 3: Setting the Perimeters Equal
Since the perimeters are equal, we can set them up as follows:
- 4s = 2 * (20 + (3/4)s).
Step 4: Solving for s
Simplifying the equation:
- 4s = 40 + (3/2)s.
- Bringing all terms with "s" on one side gives us:
- 4s - (3/2)s = 40.
- Converting 4s to a fraction:
- (8/2)s - (3/2)s = 40.
- (5/2)s = 40.
- Therefore, s = 40 * (2/5) = 16 m.
Step 5: Finding the Breadth
Now, calculate the breadth:
- Breadth = (3/4) * s = (3/4) * 16 = 12 m.
Step 6: Calculating the Area of the Rectangle
Finally, the area of the rectangle can be calculated as:
- Area = Length * Breadth = 20 m * 12 m = 240 m².
Conclusion
Thus, the area of the rectangle is 240 m², and the correct answer is option 'c'.
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The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer?
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The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? for RRB NTPC/ASM/CA/TA 2025 is part of RRB NTPC/ASM/CA/TA preparation. The Question and answers have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. Information about The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer?.
Solutions for The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for RRB NTPC/ASM/CA/TA.
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Here you can find the meaning of The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The ratio of the perimeter of the square to the perimeter of a rectangle is 1: 1. If the breadth is 3/4th times the side of square and the length of the rectangle is 20 m, then find the area of a rectangle. एक वर्ग के परिमाप और एक आयत के परिमाप का अनुपात 1: 1 है। यदि आयत की चौड़ाई, वर्ग की भुजा का 3/4 गुना है और आयत की लंबाई 20 m है, तो आयत का क्षेत्रफल ज्ञात करें।a)280 m280 m2b)320 m2320 m2c)240 m2240 m2d)300 m2300 m2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice RRB NTPC/ASM/CA/TA tests.
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