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What is the magnitude of gravitational force between earth and 1 kg object on its surface?
mass of Earth = 6 x 10^24 kg
radius of earth= 6.4x10^6 m?
mass of Earth = 6 x 10^24 kg
radius of earth= 6.4x10^6 m?
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What is the magnitude of gravitational force between earth and 1 kg ob...
Understanding Gravitational Force
To find the gravitational force between the Earth and a 1 kg object on its surface, we can use Newton's law of universal gravitation.
Formula for Gravitational Force
- The formula is given by: F = G * (m1 * m2) / r²
- F = gravitational force
- G = gravitational constant (approximately 6.674 x 10^-11 N(m/kg)²)
- m1 = mass of the first object (Earth = 6 x 10^24 kg)
- m2 = mass of the second object (1 kg object)
- r = radius of the Earth (6.4 x 10^6 m)
Calculating the Force
1. Substitute the values into the formula:
- F = (6.674 x 10^-11) * (6 x 10^24) * (1) / (6.4 x 10^6)²
2. Calculate the denominator (r²):
- (6.4 x 10^6)² = 4.096 x 10^13 m²
3. Now substitute this back into the equation:
- F = (6.674 x 10^-11 * 6 x 10^24) / (4.096 x 10^13)
4. Perform the calculation:
- F ≈ (4.0044 x 10^14) / (4.096 x 10^13)
- F ≈ 9.78 N
Conclusion
- The gravitational force between Earth and a 1 kg object on its surface is approximately 9.78 Newtons.
- This force is what we commonly refer to as the weight of the object, which is a result of Earth's gravitational pull.
To find the gravitational force between the Earth and a 1 kg object on its surface, we can use Newton's law of universal gravitation.
Formula for Gravitational Force
- The formula is given by: F = G * (m1 * m2) / r²
- F = gravitational force
- G = gravitational constant (approximately 6.674 x 10^-11 N(m/kg)²)
- m1 = mass of the first object (Earth = 6 x 10^24 kg)
- m2 = mass of the second object (1 kg object)
- r = radius of the Earth (6.4 x 10^6 m)
Calculating the Force
1. Substitute the values into the formula:
- F = (6.674 x 10^-11) * (6 x 10^24) * (1) / (6.4 x 10^6)²
2. Calculate the denominator (r²):
- (6.4 x 10^6)² = 4.096 x 10^13 m²
3. Now substitute this back into the equation:
- F = (6.674 x 10^-11 * 6 x 10^24) / (4.096 x 10^13)
4. Perform the calculation:
- F ≈ (4.0044 x 10^14) / (4.096 x 10^13)
- F ≈ 9.78 N
Conclusion
- The gravitational force between Earth and a 1 kg object on its surface is approximately 9.78 Newtons.
- This force is what we commonly refer to as the weight of the object, which is a result of Earth's gravitational pull.
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What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m?
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What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m?.
What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the magnitude of gravitational force between earth and 1 kg object on its surface? mass of Earth = 6 x 10^24 kgradius of earth= 6.4x10^6 m?.
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