The variation of velocity of a particle moving along straight line is shown in the figure. The distance travelled by the particle in 4 s is a)25mb)30mc)55md)60mCorrect answer is option 'C'. Can you explain this answer?

Question

The variation of velocity of a particle moving along straight line is shown in the figure. The distance travelled by the particle in 4 s is            a)25mb)30mc)55md)60mCorrect answer is option 'C'. Can you explain this answer?

Accepted Answer

The distance traveled is equal to the area under the curve which is equal to
S = ½ x 20 x1 + 20 x 1 +½ x 10 x1 + 10 x 2
= 10 + 20 + 5 + 20
= 55m

Answer

20 +10+10+10+5 = 55

Answer

Answer must be c)55 ,as far as  I know .( since, 10+20+5 +20=55)

Answer

We know that the areas under the graph gives us the distance traveled.so by dividing the path on the graph into shapes whose finding the areas is much easier we can crack this easily.
shape 1triangle base is 1 and height is 20 so 0.5x1x20=10 (by the formula of area of triangle). ----------------------(1)
shape 2rectanglebase is 1{2-1} and height is 20 so 1x20=20-------------_----------------------(2)
shape 3trapezium0.5xheightx(side1+side2)0.5x1x(20+10)0.5x1x3015----------------------------(3)
shape 4rectanglebxh1x1010-------------------(4)
now add all the areas (1+2+3+4)10+20+15+1055
hope you got the logic

Answer

Distance travelled by particle is area under the curve Divide figure into simple geometric figures and add their areas you will get answer.i.e. 20+10+10+10+5

Answer

By dividing the area of the graph in different shapes and finding their areas separately we get the sum of their total area to be equal to 55 which is the distance covered by the particle in 4 sec

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