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Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by?
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Force of attraction between the positive which has nucleus and the ele...
Understanding the Force of Attraction in Hydrogen Atom
The force of attraction between the nucleus and the electron in a hydrogen atom is defined by Coulomb's law. When the electron transitions from a higher orbit (R1) to a lower orbit (R2), the total energy of the atom changes.
Energy Levels in Hydrogen Atom
- The energy levels for an electron in a hydrogen atom can be expressed as:
- E_n = - (k * e^2) / (2 * n^2)
- Here, k is the Coulomb's constant, e is the charge of the electron, and n is the principal quantum number.
Initial and Final Energies
- For the initial orbit (R1), the energy is:
- E_initial = - (k * e^2) / (2 * n1^2)
- For the final orbit (R2), the energy is:
- E_final = - (k * e^2) / (2 * n2^2)
Decrease in Total Energy
- The decrease in total energy (ΔE) when the electron jumps from R1 to R2 is given by:
- ΔE = E_final - E_initial
- ΔE = [ - (k * e^2) / (2 * n2^2) ] - [ - (k * e^2) / (2 * n1^2) ]
- ΔE = (k * e^2) / 2 * (1/n1^2 - 1/n2^2)
Conclusion
- The decrease in total energy indicates that the electron is losing energy as it moves closer to the nucleus. This process corresponds to the emission of a photon, representing the energy lost during the transition.
The quantization of energy levels in atoms is fundamental to understanding atomic structure and spectral lines.
The force of attraction between the nucleus and the electron in a hydrogen atom is defined by Coulomb's law. When the electron transitions from a higher orbit (R1) to a lower orbit (R2), the total energy of the atom changes.
Energy Levels in Hydrogen Atom
- The energy levels for an electron in a hydrogen atom can be expressed as:
- E_n = - (k * e^2) / (2 * n^2)
- Here, k is the Coulomb's constant, e is the charge of the electron, and n is the principal quantum number.
Initial and Final Energies
- For the initial orbit (R1), the energy is:
- E_initial = - (k * e^2) / (2 * n1^2)
- For the final orbit (R2), the energy is:
- E_final = - (k * e^2) / (2 * n2^2)
Decrease in Total Energy
- The decrease in total energy (ΔE) when the electron jumps from R1 to R2 is given by:
- ΔE = E_final - E_initial
- ΔE = [ - (k * e^2) / (2 * n2^2) ] - [ - (k * e^2) / (2 * n1^2) ]
- ΔE = (k * e^2) / 2 * (1/n1^2 - 1/n2^2)
Conclusion
- The decrease in total energy indicates that the electron is losing energy as it moves closer to the nucleus. This process corresponds to the emission of a photon, representing the energy lost during the transition.
The quantization of energy levels in atoms is fundamental to understanding atomic structure and spectral lines.
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Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by?
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Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by?.
Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Force of attraction between the positive which has nucleus and the electron in a hydrogen atom is given by f is equals to k into a square upon r square asume that the nucleus is fixed the electron is initially moving in a orbit of radius R1 jumps into orbit of smaller radius R2 the decrease in the total energy of the atom is given by?.
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