If in a Delta*ABC Delta = a ^ 2 - (b - c) ^ 2 then tan A =?
Understanding the Problem
To find tan A in triangle ABC given the expression for Delta (area), we start with the formula provided:
Delta = a^2 - (b - c)^2.
This expression can be interpreted geometrically in the context of triangle properties.
Using the Area of Triangle
- The area of a triangle can be expressed using the formula:
Area = (1/2) * base * height.
- Alternatively, using the sides and the angle, we can also express the area as:
Area = (1/2) * b * c * sin A.
Relating Delta to Triangle Properties
- The expression for Delta can be simplified as:
Delta = a^2 - (b^2 - 2bc + c^2) = a^2 + 2bc - b^2 - c^2.
- This representation connects the lengths of the sides to the area, which is essential for finding tan A.
Applying the Law of Sines
- By the Law of Sines, we know:
a/sin A = b/sin B = c/sin C.
- Therefore, we can express sin A in terms of a, b, and c:
sin A = a / (b * sin B).
Finding Tan A
- The tangent of angle A can be expressed using the sine and cosine:
tan A = sin A / cos A.
- Using the relation:
cos A = (b^2 + c^2 - a^2) / (2bc),
- Hence, we can derive:
tan A = (2 * Delta) / (b * c * (b^2 + c^2 - a^2)).
This gives us a complete understanding of how to find tan A using the given area formula in Delta ABC.