Class 11 Exam > Class 11 Questions > A police car is travelling in a straight line...
Start Learning for Free
A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of v
- a)10 ms-1
- b)15 ms-1
- c)20 ms-1
- d)30 ms-1
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A police car is travelling in a straight line with a constantspeed v. ...
Most Upvoted Answer
A police car is travelling in a straight line with a constantspeed v. ...
Solution:
Given,
Truck velocity, v' = 3v/2
Police car acceleration, a = 3 m/s^2
Time taken by police car to catch the truck, t = 10 s
To find:
The value of velocity of the police car, v
Let's assume that the distance travelled by the truck before the police car starts acceleration is d. Therefore, the distance between the truck and the police car at t = 0 is d.
When the police car starts accelerating, the relative velocity between the truck and the police car is (3v/2 - v) = v/2.
Let's calculate the distance travelled by the truck during the time taken by the police car to start acceleration.
Distance travelled by the truck = v' * t
= (3v/2) * 10
= 15v
Therefore, the distance between the truck and the police car at the time when the police car starts accelerating is d - 15v.
After 10 seconds of acceleration, the velocity of the police car becomes v + at = v + 3*10 = v + 30 m/s.
Let's calculate the distance travelled by the police car during the time it takes to catch up with the truck.
Distance travelled by the police car = (1/2) * a * t^2 + v*t
= (1/2) * 3 * 10^2 + (v + 30) * 10
= 150 + 10v + 300
= 10v + 450
The distance travelled by the truck during this time is (d - 15v) + 10v = d - 5v.
Since the police car catches up with the truck, the distance travelled by both vehicles is the same.
Therefore, 10v + 450 = d - 5v
Simplifying the above equation, we get
15v = d - 450
Substituting the value of d = v' * t = (3v/2) * 10 = 15v, we get
15v = 15v - 450
Therefore, the value of v is 15 m/s.
Hence, the correct option is (b) 15 ms^-1.
Given,
Truck velocity, v' = 3v/2
Police car acceleration, a = 3 m/s^2
Time taken by police car to catch the truck, t = 10 s
To find:
The value of velocity of the police car, v
Let's assume that the distance travelled by the truck before the police car starts acceleration is d. Therefore, the distance between the truck and the police car at t = 0 is d.
When the police car starts accelerating, the relative velocity between the truck and the police car is (3v/2 - v) = v/2.
Let's calculate the distance travelled by the truck during the time taken by the police car to start acceleration.
Distance travelled by the truck = v' * t
= (3v/2) * 10
= 15v
Therefore, the distance between the truck and the police car at the time when the police car starts accelerating is d - 15v.
After 10 seconds of acceleration, the velocity of the police car becomes v + at = v + 3*10 = v + 30 m/s.
Let's calculate the distance travelled by the police car during the time it takes to catch up with the truck.
Distance travelled by the police car = (1/2) * a * t^2 + v*t
= (1/2) * 3 * 10^2 + (v + 30) * 10
= 150 + 10v + 300
= 10v + 450
The distance travelled by the truck during this time is (d - 15v) + 10v = d - 5v.
Since the police car catches up with the truck, the distance travelled by both vehicles is the same.
Therefore, 10v + 450 = d - 5v
Simplifying the above equation, we get
15v = d - 450
Substituting the value of d = v' * t = (3v/2) * 10 = 15v, we get
15v = 15v - 450
Therefore, the value of v is 15 m/s.
Hence, the correct option is (b) 15 ms^-1.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer?
Question Description
A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer?.
A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer?.
Solutions for A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A police car is travelling in a straight line with a constantspeed v. A truck travelling in the same direction withconstant velocity 3v/2 passes, the police car at t = 0.The police car starts acceleration 10s after passing thetruck, at a constant rate of 3 ms-2, while truck continuesto move at constant speed. If the poilce car takes 10 sfurther to catch the truck, find the value of va)10 ms-1b)15 ms-1c)20 ms-1d)30 ms-1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup