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What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how?
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What will be the ratio of the distance moved by a freely falling body ...
Ratio of distance moved by a freely falling body from rest in 4th and 5th second of a journey
What is freely falling body?
A freely falling body is an object that is in a state of free fall, which means that it is only influenced by the force of gravity. This means that the object is not being pushed or pulled in any other direction, and its only acceleration is due to gravity.
What is the formula for distance travelled by a freely falling body?
The formula for distance travelled by a freely falling body can be expressed as:
d = 1/2 * g * t^2
where d is the distance travelled, g is the acceleration due to gravity, and t is the time for which the object has been falling.
Calculating the ratio of distance moved by a freely falling body from rest in 4th and 5th second of a journey
Let us assume that the acceleration due to gravity is 9.8 m/s^2 (which is the standard value for the acceleration due to gravity on Earth).
Using the formula for distance travelled by a freely falling body, we can calculate the distance travelled in the 4th and 5th seconds of the journey as follows:
- Distance travelled in 4th second = 1/2 * 9.8 * (4^2) = 78.4 meters
- Distance travelled in 5th second = 1/2 * 9.8 * (5^2) = 122.5 meters
Therefore, the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey is:
78.4 : 122.5
Simplifying this ratio, we get:
7 : 9
Conclusion
Therefore, the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey is 7:9.
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What will be the ratio of the distance moved by a freely falling body ...
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What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how?
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What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how?.
What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th second of a journey? the answer is 7:9 pls explain how?.
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