**Explanation:**

The given electronic configuration is 1s22s22p1. Let's break it down step by step to determine which element it belongs to.

1. The first digit represents the principal energy level, which is determined by the period number in the periodic table. In this case, the first digit is 1, which means it belongs to the first period.

2. The second digit represents the subshell (or orbital) within the principal energy level. In this case, the second digit is 2, which means it belongs to the s subshell.

3. The superscript numbers represent the number of electrons in each subshell. The first subshell (1s) has 2 electrons, the second subshell (2s) also has 2 electrons, and the third subshell (2p) has 1 electron.

Based on this information, we can conclude that the electronic configuration 1s22s22p1 belongs to the element boron (B).

**Reasoning:**

- Beryllium (Be) has an electronic configuration of 1s22s2, which does not match the given configuration.

- Lithium (Li) has an electronic configuration of 1s22s1, which also does not match the given configuration.

- Carbon (C) has an electronic configuration of 1s22s22p2, which again does not match the given configuration.

- Boron (B), on the other hand, has an electronic configuration of 1s22s22p1, which exactly matches the given configuration.

Therefore, the correct answer is option C, Boron.

Boron atomic no. is 5.... so, its electronic configuration is 1s^2 2s^2 2p^1.....s orbital can accommodate 2 electrons., while p orbital can accommodate 6 electrons., d orbital can accommodate 10 electrons and f orbital can accommodate 14 electrons.....in increasing order of energy electrons are being filled in these orbitals.....