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The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?
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The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?
Calculating the Sum of the Series 3.6 4.7 5.8 upto (n-2) terms
The given series is:
3.6 4.7 5.8 ... upto (n-2) terms
Understanding the Given Series
The given series is an arithmetic progression with:
- First term (a) = 3.6
- Common difference (d) = 1.1
- Last term (l) = (n-2)d + a
Using the formula for the sum of an arithmetic progression, we can calculate the sum of the given series.
Formula for the Sum of an Arithmetic Progression
The formula for the sum of an arithmetic progression is:
(n/2)(2a + (n-1)d)
Calculating the Sum of the Given Series
Substituting the values of a, d, and l in the formula for the sum of an arithmetic progression, we get:
(n/2)(2(3.6) + (n-3)(1.1))
Simplifying the above expression, we get:
(n/2)(7.2 + 1.1n - 3.3)
(n/2)(1.1n + 3.9)
0.55n^2 + 1.95n
Therefore, the sum of the series 3.6 4.7 5.8 ... upto (n-2) terms is:
0.55n^2 + 1.95n
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The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?
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The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?
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The sum of the series 3.6+4.7+5.8+.upto (n-2)terms? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The sum of the series 3.6+4.7+5.8+.upto (n-2)terms? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?.
The sum of the series 3.6+4.7+5.8+.upto (n-2)terms? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The sum of the series 3.6+4.7+5.8+.upto (n-2)terms? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the series 3.6+4.7+5.8+.upto (n-2)terms?.
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