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Factorise by splitting the middle term 2x2 - 11x + 12
- a)(2x+3)(x+4)
- b)(x+3)(2x-4)
- c)(x-3)(2x-4)
- d)(2x-3)(x-4)
Correct answer is option 'D'. Can you explain this answer?
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Factorise by splitting the middle term2x2- 11x + 12a)(2x+3)(x+4)b)(x+3...
Solution:
The given expression is 2x² - 11x + 12
To factorise this expression, we need to find two numbers whose product is 2 × 12 = 24 and whose sum is -11.
Let's list all the possible pairs of numbers whose product is 24.
1 × 24
2 × 12
3 × 8
4 × 6
Out of these pairs, the only pair whose sum is -11 is 3 and -8.
Therefore, we can split the middle term as -8x + 3x.
2x² - 8x + 3x + 12
Now, we can factorise the expression by grouping.
2x(x - 4) + 3(x - 4)
(2x + 3)(x - 4)
Hence, the correct answer is option 'D': (2x - 3)(x - 4).
The given expression is 2x² - 11x + 12
To factorise this expression, we need to find two numbers whose product is 2 × 12 = 24 and whose sum is -11.
Let's list all the possible pairs of numbers whose product is 24.
1 × 24
2 × 12
3 × 8
4 × 6
Out of these pairs, the only pair whose sum is -11 is 3 and -8.
Therefore, we can split the middle term as -8x + 3x.
2x² - 8x + 3x + 12
Now, we can factorise the expression by grouping.
2x(x - 4) + 3(x - 4)
(2x + 3)(x - 4)
Hence, the correct answer is option 'D': (2x - 3)(x - 4).
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Factorise by splitting the middle term2x2- 11x + 12a)(2x+3)(x+4)b)(x+3)(2x-4)c)(x-3)(2x-4)d)(2x-3)(x-4)Correct answer is option 'D'. Can you explain this answer?
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