Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider a hypothetical system with byte-addr...
Start Learning for Free
Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?
- a)32-32
- b)324-321
- c)327-326
- d)329-322
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Consider a hypothetical system with byte-addressable memory, 64-bit lo...
Data
1 word (W) = 1 byte (B)
Logical address = 264 B
page size = 8 MB = 223 B
page table entry (PTE) = 16 B
Formula:
Page table size (PTS) = number of pages × PTE
Calculation:
number of pages = 264 / 223=241
Page table size (PTS) = number of pages × y
PTS = 241 × 16B=245B
∴ PTS = 32 TB
Important points
1 TB = 240 B
where B stands for byte
Free Test
FREE
| Start Free Test |
Community Answer
Consider a hypothetical system with byte-addressable memory, 64-bit lo...
Understanding the System Components
- Logical Address Space: The system has a 64-bit logical address space, which means it can address 2^64 bytes of memory.
- Page Size: Each page in this system is 8 Megabytes (MB). This is equivalent to 2^23 bytes (since 1 MB = 2^20 bytes).
- Page Table Entry Size: Each page table entry is 16 bytes.
Calculating the Number of Pages
- Total Memory: The total memory addressable by the system is 2^64 bytes.
- Number of Pages: To find the number of pages, divide the total addressable memory by the page size:
- Number of pages = Total addressable memory / Page size
- Number of pages = 2^64 bytes / 2^23 bytes = 2^(64-23) = 2^41 pages.
Calculating the Page Table Size
- Size of the Page Table: The size of the page table can be calculated by multiplying the number of pages by the size of each page table entry:
- Page table size = Number of pages * Size of each page table entry
- Page table size = 2^41 pages * 16 bytes = 2^41 * 2^4 = 2^45 bytes.
Converting to Terabytes
- Bytes to Terabytes Conversion:
- 1 Terabyte (TB) = 2^40 bytes.
- Therefore, Page table size in TB = Page table size in bytes / 2^40 bytes = 2^45 / 2^40 = 2^5 = 32 TB.
Conclusion
The size of the page table in this system is 32 Terabytes, confirming that option 'A' is indeed correct.
- Logical Address Space: The system has a 64-bit logical address space, which means it can address 2^64 bytes of memory.
- Page Size: Each page in this system is 8 Megabytes (MB). This is equivalent to 2^23 bytes (since 1 MB = 2^20 bytes).
- Page Table Entry Size: Each page table entry is 16 bytes.
Calculating the Number of Pages
- Total Memory: The total memory addressable by the system is 2^64 bytes.
- Number of Pages: To find the number of pages, divide the total addressable memory by the page size:
- Number of pages = Total addressable memory / Page size
- Number of pages = 2^64 bytes / 2^23 bytes = 2^(64-23) = 2^41 pages.
Calculating the Page Table Size
- Size of the Page Table: The size of the page table can be calculated by multiplying the number of pages by the size of each page table entry:
- Page table size = Number of pages * Size of each page table entry
- Page table size = 2^41 pages * 16 bytes = 2^41 * 2^4 = 2^45 bytes.
Converting to Terabytes
- Bytes to Terabytes Conversion:
- 1 Terabyte (TB) = 2^40 bytes.
- Therefore, Page table size in TB = Page table size in bytes / 2^40 bytes = 2^45 / 2^40 = 2^5 = 32 TB.
Conclusion
The size of the page table in this system is 32 Terabytes, confirming that option 'A' is indeed correct.
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Top Courses for Computer Science Engineering (CSE)View all
Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer?
Question Description
Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer?.
Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer?.
Solutions for Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a hypothetical system with byte-addressable memory, 64-bit logical addresses, 8 Megabyte page size and page table entries of 16 bytes each. What is the size of the page table in the system in terabytes?a)32-32b)324-321c)327-326d)329-322Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
|
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup