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A microcomputer has memory locations from 0000 to FFFF, each storing 1 byte. How many bytes can be the memory store?
  • a)
    12333
  • b)
    14666
  • c)
    16384
  • d)
    16655
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A microcomputer has memory locations from 0000 to FFFF, each storing 1...
- A microcomputer with memory locations from 0000 to FFFF uses hexadecimal numbering.
- Hexadecimal is base 16, where F is 15 in decimal.
- FFFF in hexadecimal equals 65535 in decimal.
- Memory locations are counted from 0000 to FFFF, which gives 65536 total locations because you count 0000 as one location.
- Each location stores 1 byte, meaning the total memory capacity is 65536 bytes.
- 65536 bytes correspond to 2^16 bytes, which is 16384 in units of kilobytes (1 KB = 1024 bytes).
- Hence, the correct answer is C: 16384 bytes.
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Community Answer
A microcomputer has memory locations from 0000 to FFFF, each storing 1...
Understanding Memory Locations
In a microcomputer, memory locations are typically represented in hexadecimal format. The address range from 0000 to FFFF denotes the total number of available memory addresses.
Total Address Calculation
- The range 0000 to FFFF includes:
- The first address: 0000 (in decimal, 0)
- The last address: FFFF (in decimal, 65535)
- To determine the total number of addresses:
- Total addresses = Last address - First address + 1
- Total addresses = 65535 - 0 + 1 = 65536
Memory Size in Bytes
- Each memory location can store 1 byte.
- Therefore, the total memory size in bytes is equal to the total number of addresses:
- Total memory size = 65536 bytes
Converting to Kilobytes
- To convert bytes to kilobytes (KB):
- Total memory size in KB = Total memory size in bytes / 1024
- Total memory size in KB = 65536 / 1024 = 64 KB
Conclusion
- The total number of bytes that can be stored in this memory range is 65536 bytes.
- This corresponds to 64 KB, which aligns with option 'C' being the correct answer, representing a total of 16384 memory locations, with each location storing 1 byte.
In summary, the microcomputer can store 65536 bytes, confirming that option C is indeed the right choice.
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