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The trigonometric Fourier series expansion of an odd function shall have
  • a)
    only sine terms
  • b)
    only cosine terms
  • c)
    odd harmonics of both sine and cosine terms
  • d)
    none of the these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The trigonometric Fourier series expansion of an odd function shall ha...
Understanding the Fourier Series of Odd Functions
When considering the Fourier series expansion of functions, it's important to understand how different types of functions (even, odd) affect the series representation.
Odd Functions
- An odd function is defined by the property f(-x) = -f(x).
- This symmetry implies that the function is symmetric about the origin.
Fourier Series Components
The Fourier series expansion of a periodic function can be expressed as:
- f(x) = a0/2 + Σ [an * cos(nωx) + bn * sin(nωx)]
Where:
- a0 is the average value of the function.
- an are the coefficients for the cosine terms (even functions).
- bn are the coefficients for the sine terms (odd functions).
Why Only Sine Terms for Odd Functions?
- For odd functions, the average value (a0) is zero because the positive and negative areas cancel each other out over one period.
- The cosine terms (an) are eliminated because they represent even functions, which do not satisfy the symmetry of odd functions.
- Thus, only sine terms (bn) remain, representing the odd harmonics of the function.
Conclusion
In conclusion, when performing a Fourier series expansion for an odd function, the result will contain only sine terms. Therefore, the correct answer is:
- a) only sine terms.
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