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The supply voltage to an induction motor is reduced by 10%. By what percentage,approximately, will the maximum torque decrease
- a)5%
- b)10%
- c)20%
- d)40%
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The supply voltage to an induction motor is reduced by 10%. By what pe...
T is directly proportional to square of the voltage…So Torque which can be delivered by the motor is proportional to square of the operating voltage. When the supply voltage increases by 10%, it becomes 1.1 times and therefore torque becomes 1.1^2 = 1.21 times i.e. 21% increase. When supply voltage reduces by 10%, it becomes 0.9 times, therefore torque becomes 0.9^2 times i.e. 0.81 times i.e. 19% less. Hence we can say that 10% change in supply voltage results in 20% change in torque.
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The supply voltage to an induction motor is reduced by 10%. By what pe...
Given: Supply voltage to an induction motor is reduced by 10%
We need to find: Percentage decrease in maximum torque
Explanation:
- Induction motor torque is proportional to the square of the applied voltage.
- Let's assume the initial voltage applied to the motor is V, then the torque produced by the motor is proportional to V^2.
- When the supply voltage is reduced by 10%, the new voltage applied to the motor is 0.9V.
- The new torque produced by the motor is proportional to (0.9V)^2 = 0.81V^2.
- The percentage decrease in torque can be calculated as follows:
Percentage decrease = (Initial torque - New torque) / Initial torque * 100
= (V^2 - 0.81V^2) / V^2 * 100
= (1 - 0.81) * 100
= 19%
Therefore, the maximum torque will decrease by approximately 20% when the supply voltage to an induction motor is reduced by 10%. Thus, option C is the correct answer.
We need to find: Percentage decrease in maximum torque
Explanation:
- Induction motor torque is proportional to the square of the applied voltage.
- Let's assume the initial voltage applied to the motor is V, then the torque produced by the motor is proportional to V^2.
- When the supply voltage is reduced by 10%, the new voltage applied to the motor is 0.9V.
- The new torque produced by the motor is proportional to (0.9V)^2 = 0.81V^2.
- The percentage decrease in torque can be calculated as follows:
Percentage decrease = (Initial torque - New torque) / Initial torque * 100
= (V^2 - 0.81V^2) / V^2 * 100
= (1 - 0.81) * 100
= 19%
Therefore, the maximum torque will decrease by approximately 20% when the supply voltage to an induction motor is reduced by 10%. Thus, option C is the correct answer.
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