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The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode?
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The electricity os passed througj Ni(No3)2 solution using platinum ele...
Introduction:
In this scenario, electricity is passed through a solution of Ni(NO3)2 using a platinum electrode. The weight of the substance is given as 1.36×10^-3. We need to determine the weight of the substance on the other electrode.
Explanation:
To understand the process, we need to consider the electrolysis of the Ni(NO3)2 solution. During electrolysis, the positive ions (cations) are attracted to the negative electrode (cathode), while the negative ions (anions) are attracted to the positive electrode (anode).
Electrolysis of Ni(NO3)2:
When Ni(NO3)2 is dissolved in water, it dissociates into Ni2+ cations and NO3- anions. During electrolysis, the Ni2+ cations will be attracted to the cathode (negative electrode) and undergo reduction, while the NO3- anions will be attracted to the anode (positive electrode) and undergo oxidation.
Cathode (Reduction):
At the cathode, Ni2+ cations will gain electrons and be reduced to metallic nickel (Ni):
Ni2+ + 2e- → Ni
The reduction of Ni2+ cations at the cathode results in the deposition of metallic nickel on the electrode surface.
Weight Calculation:
To determine the weight of the substance on the other electrode, we need to consider the stoichiometry of the reaction. From the balanced equation, we can see that for every 2 moles of electrons gained, 1 mole of Ni is deposited.
Given the weight of the substance is 1.36×10^-3, we can calculate the moles of Ni deposited using its molar mass (58.69 g/mol):
Moles of Ni = Weight of substance / Molar mass of Ni
Moles of Ni = 1.36×10^-3 / 58.69
Once we have the moles of Ni deposited, we can use the stoichiometry to calculate the weight of the substance on the other electrode.
Weight of the substance on the other electrode = Moles of Ni × Molar mass of Ni
Conclusion:
The weight of the substance on the other electrode can be calculated by determining the moles of Ni deposited using the given weight of the substance and its molar mass. Then, using the stoichiometry of the reaction, we can calculate the weight of the substance on the other electrode.
In this scenario, electricity is passed through a solution of Ni(NO3)2 using a platinum electrode. The weight of the substance is given as 1.36×10^-3. We need to determine the weight of the substance on the other electrode.
Explanation:
To understand the process, we need to consider the electrolysis of the Ni(NO3)2 solution. During electrolysis, the positive ions (cations) are attracted to the negative electrode (cathode), while the negative ions (anions) are attracted to the positive electrode (anode).
Electrolysis of Ni(NO3)2:
When Ni(NO3)2 is dissolved in water, it dissociates into Ni2+ cations and NO3- anions. During electrolysis, the Ni2+ cations will be attracted to the cathode (negative electrode) and undergo reduction, while the NO3- anions will be attracted to the anode (positive electrode) and undergo oxidation.
Cathode (Reduction):
At the cathode, Ni2+ cations will gain electrons and be reduced to metallic nickel (Ni):
Ni2+ + 2e- → Ni
The reduction of Ni2+ cations at the cathode results in the deposition of metallic nickel on the electrode surface.
Weight Calculation:
To determine the weight of the substance on the other electrode, we need to consider the stoichiometry of the reaction. From the balanced equation, we can see that for every 2 moles of electrons gained, 1 mole of Ni is deposited.
Given the weight of the substance is 1.36×10^-3, we can calculate the moles of Ni deposited using its molar mass (58.69 g/mol):
Moles of Ni = Weight of substance / Molar mass of Ni
Moles of Ni = 1.36×10^-3 / 58.69
Once we have the moles of Ni deposited, we can use the stoichiometry to calculate the weight of the substance on the other electrode.
Weight of the substance on the other electrode = Moles of Ni × Molar mass of Ni
Conclusion:
The weight of the substance on the other electrode can be calculated by determining the moles of Ni deposited using the given weight of the substance and its molar mass. Then, using the stoichiometry of the reaction, we can calculate the weight of the substance on the other electrode.
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The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode?
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The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode?.
The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electricity os passed througj Ni(No3)2 solution using platinum electrode the substance weigh is 1.36×10^-3 find the weight of the substance on other electrode?.
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