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ABC is a right angle triangle in which AB = 3 cm and BC = 4 cm and angle ABC is = π2 . The three charges + 15, + 12 and -20 e.s.u are placed respectively and A , B and C . the force acting on b is125 dynes 35 dynes25 dyneszero
Verified Answer
ABC is a right angle triangle in which AB = 3 cm and BC = 4 cm and ang...
The net force on B can be calculated as follows
FNet = √FA2 + FC2
Now calculate FA and FC
FA = (15 Χ 12) / (32)
FA = 20 dyen
FC = (12 Χ 20) / (42)
FC = 15 dyen.
FNet = √FA2 + FC2
FNet = √(20)2 + (15)2
FNet = 25 dyen.
This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
ABC is a right angle triangle in which AB = 3 cm and BC = 4 cm and ang...
Explanation:
Given Information:
- Side AB = 3 cm
- Side BC = 4 cm
- Angle ABC = π/2
- Charges placed at points A, B, and C are +15 e.s.u, +12 e.s.u, and -20 e.s.u respectively
Calculation of Force on Charge B:
- The force acting on charge B can be calculated using Coulomb's law which states that the force between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.
- In this case, the force on charge B due to charge A can be calculated as FAB = k * (q1 * q2) / r^2, where k is the Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
- Similarly, the force on charge B due to charge C can be calculated as FBC = k * (q1 * q2) / r^2.
- The total force on charge B is the vector sum of the forces due to charges A and C, which can be calculated using vector addition.
Calculation of Magnitudes of Forces:
- Given the charges at points A, B, and C are +15, +12, and -20 e.s.u respectively, the magnitudes of the forces can be calculated using the formula mentioned above.
- The distance between charges A and B (AB) is 3 cm, and the distance between charges B and C (BC) is 4 cm.
Final Answer:
- After calculating the forces due to charges A and C, the total force acting on charge B can be determined as 25 dynes.
- The direction of the force would be towards charge A due to the repulsion between like charges.
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ABC is a right angle triangle in which AB = 3 cm and BC = 4 cm and angle ABC is = π2 . The three charges + 15, + 12 and -20 e.s.u are placed respectively and A , B and C . the force acting on b is125 dynes 35 dynes25 dyneszero
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